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pythagoras
(a – b)² = a² – 2ab + b²
•
(4p)² + (4p – 5)² = (6p – 5)²
misal :
2p = a
(2a)² + (2a – 5)² = (3a – 5)²
4a² + 4a² – 20a + 25 = 9a² – 30a + 25
8a² – 9a² – 20a + 30a = 0
-a² + 10a = 0
a² – 10a = 0
a(a – 10) = 0
a = 0 atau a = 10
a = 0
2p = 0
p = 0
a = 10
2p = 10
p = 5
nilai p yang memenuhi → p = 5
sisi 1 = 4p = 4 × 5 = 20 cm
sisi 2 = 4p – 5 = 20 – 5 = 15 cm
sisi 3 = 6p – 5 = 6.5 – 5 = 25 cm
keliling segitiga = 15 + 20 + 25 = 60 cm