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tentukan nilai x yang memenuhi persamaan |4x -10|=-10
|4x - 10| = -10 nilai mutlak selalu bernilai positif, tidak mungkin bernilai (-10) negatif. tidak ada nilai x yg memenuhi HP = { }
|4x – 10| = -10
nilai mutlak selalu bernilai positif, tidak mungkin bernilai (-10) negatif.
tidak ada nilai x yg memenuhi
HP = { }
See lessJika diketahui x=√5 dan y=√7 , nilai √350 adalah
aljabar x = √5 → x² = 5 y = √7 √350 = √(2 × 5² × 7) = 5 × √2 × √7 = x² × √2 × y = √2 x²y = x²y√2
aljabar
x = √5 → x² = 5
y = √7
√350
= √(2 × 5² × 7)
= 5 × √2 × √7
= x² × √2 × y
= √2 x²y
= x²y√2
See lessMtk nihhhhhh……..
notasi ilmiah a × 10ⁿ 1 < a < 10 n bilangan bulat 0,000062 = 62/1000000 = 62 × 10^-6 = 6,2 × 10 × 10^-6 = 6,2 × 10^-5 • 125000000 = 125 × 1000000 = 1,25 × 100 × 1000000 = 1,25 × 10² × 10⁶ = 1,25 × 10⁸
notasi ilmiah
a × 10ⁿ
1 < a < 10
n bilangan bulat
0,000062
= 62/1000000
= 62 × 10^-6
= 6,2 × 10 × 10^-6
= 6,2 × 10^–5
•
125000000
= 125 × 1000000
= 1,25 × 100 × 1000000
= 1,25 × 10² × 10⁶
= 1,25 × 10⁸
See lessTolong dong kak yg bagian a dan d nya saja
persamaan trigonometri a. 2 sin² x - 7 sin x + 3 = 0 (2 sin x - 1)(sin x - 3) = 0 sin x = 1/2 atau sin x = 3 TM sin x = 1/2 x = 30° + k.360° ... (1) sin x = 1/2 x = 150° + k.360°... (2) k bilangan bulat [0°,360°] HP = {30° , 150°} d. 3 sin x + cos² x - 3 = 0 3 sinRead more
persamaan trigonometri
a.
2 sin² x – 7 sin x + 3 = 0
(2 sin x – 1)(sin x – 3) = 0
sin x = 1/2 atau sin x = 3 TM
sin x = 1/2
x = 30° + k.360° … (1)
sin x = 1/2
x = 150° + k.360°… (2)
k bilangan bulat
[0°,360°]
HP = {30° , 150°}
d.
3 sin x + cos² x – 3 = 0
3 sin x + (1 – sin² x) – 3 = 0
sin² x – 3 sin x + 2 = 0
(sin x – 1)(sin x – 2) = 0
sin x = 1 atau sin x = 2 TM
sin x = 1
x = 90° + k.360°
[0° , 360°]
HP = {90°}
See lessDiketahui kubus ABCD.EFGH dengan panjang rusuk 6 cm. tentukan jarak titik c ke garis FH
dimensi tiga kubus r = 6 cm O tengah FH EG = r√2 = 6√2 cm GO = 1/2 EG = 3√2 cm CO ⊥ HF Jarak C ke FH = CO = √(CG² +GO²) = 1/2 r√6 = 3√6 cm
dimensi tiga
kubus
r = 6 cm
O tengah FH
EG = r√2 = 6√2 cm
GO = 1/2 EG = 3√2 cm
CO ⊥ HF
Jarak C ke FH
= CO
= √(CG² +GO²)
= 1/2 r√6
= 3√6 cm
See lessKak tolong kak Buat besok di kumpulkan
persamaam kuadrat melengkapkan kuadrat sempurna (a - b)² = a² - 2ab + b² x² - 20x + 36 = 0 x² - 2.10x + 10² = -36 + 10² (x - 10)² = 64 (x - 10)² = 8² atau (x - 10)² = (-8)² x - 10 = 8 → x = 18 atau x - 10 = -8 → x = 2 HP = {2 , 18}
persamaam kuadrat
melengkapkan kuadrat sempurna
(a – b)² = a² – 2ab + b²
x² – 20x + 36 = 0
x² – 2.10x + 10² = -36 + 10²
(x – 10)² = 64
(x – 10)² = 8² atau (x – 10)² = (-8)²
x – 10 = 8 → x = 18
atau
x – 10 = -8 → x = 2
HP = {2 , 18}
See lessTentukan himpunan (hp) dari pertidaksamaan berikut menggunakan sifat |14-2x|<4
nilai mutlak |x| < a → -a < x < a • |14 - 2x| < 4 -4 < 14 - 2x < 4 -4 - 14 < 14 - 2x - 14 < 4 - 14 -18 < -2x < -10 -18/-2 > -2x/-2 > -10/-2 9 > x > 5 5 < x < 9 HP = {x| 5 < x < 9, x ∈ R}
nilai mutlak
|x| < a → -a < x < a
•
|14 – 2x| < 4
-4 < 14 – 2x < 4
-4 – 14 < 14 – 2x – 14 < 4 – 14
-18 < -2x < -10
-18/-2 > -2x/-2 > -10/-2
9 > x > 5
5 < x < 9
HP = {x| 5 < x < 9, x ∈ R}
See less