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Lim x->0 2x dikurang sin 6x per tan 6X
limit 0/0 lim x→0 (ax - sin bx)/tan cx = (a - b)/c • lim x→0 (2x - sin 6x)/tan 6x = (2 - 6)/6 = -4/6 = -2/3
limit 0/0
lim x→0 (ax – sin bx)/tan cx = (a – b)/c
•
lim x→0 (2x – sin 6x)/tan 6x
= (2 – 6)/6
= -4/6
= -2/3
See lessTentukan penyelesaian dari persamaan mutlak berikut
nilai mutlak a. |3x + 2| = 6 - 4x 3x + 2 = 6 - 4x 3x + 4x = 6 - 2 7x = 4 x = 4/7 3x + 2 = -(6 - 4x) 3x - 4x = -6 - 2 -x = -8 x = 8 syarat : 6 - 4x ≥ 0 4x ≤ 6 x ≤ 6/4 x ≤ 3/2 nilai x yg memenuhi : x = 4/7 b. |a| = b → (a + b)(a - b) = 0 dan b ≥ 0 |3x + 8| = 4Read more
nilai mutlak
a.
|3x + 2| = 6 – 4x
3x + 2 = 6 – 4x
3x + 4x = 6 – 2
7x = 4
x = 4/7
3x + 2 = -(6 – 4x)
3x – 4x = -6 – 2
-x = -8
x = 8
syarat :
6 – 4x ≥ 0
4x ≤ 6
x ≤ 6/4
x ≤ 3/2
nilai x yg memenuhi :
x = 4/7
b.
|a| = b → (a + b)(a – b) = 0
dan b ≥ 0
|3x + 8| = 4 – 2x
(x + 12)(5x + 4) = 0
x = -12 atau x = -4/5
syarat :
4 – 2x ≥ 0
x ≤ 2
nilai x :
-4/5 dan -12
See lessNilai x yang memenuhi persamaan
eksponen 25^(x² - 5x + 7) = (1/25)^(x - x² - 15) 25^(x² - 5x + 7) = 25^-(x - x² - 15) lihat pangkat nya x² - 5x + 7 = -x + x² + 15 -5x + x = 15 - 7 -4x = 8 x = 8/-4 x = -2
eksponen
25^(x² – 5x + 7) = (1/25)^(x – x² – 15)
25^(x² – 5x + 7) = 25^-(x – x² – 15)
lihat pangkat nya
x² – 5x + 7 = -x + x² + 15
-5x + x = 15 – 7
-4x = 8
x = 8/-4
x = -2
See lessRasionalkan bentuk akar berikut ini ke bentuk paling sederhana
aljabar √2 / 3√8 = √2 / (3 × √4 × √2) = 1/(3 × √4) = 1/(3 × 2) = 1/6
aljabar
√2 / 3√8
= √2 / (3 × √4 × √2)
= 1/(3 × √4)
= 1/(3 × 2)
= 1/6
See lessdiketahui kubus ABCD,EFGH dengan panjang rusuk 4cm tentukan,1.jarak titik F ke garis CE tolong di bantu MLM ini di kumpul soalnya
dimensi tiga kubus r = 4 cm ∆CFE siku di F X pada CE FX ⊥ CE Jarak F ke CE = FX = EF × FC / EC = r × r√2 / r√3 = 1/3 r√6 = 4/3 √6 cm
dimensi tiga
kubus
r = 4 cm
∆CFE siku di F
X pada CE
FX ⊥ CE
Jarak F ke CE
= FX
= EF × FC / EC
= r × r√2 / r√3
= 1/3 r√6
= 4/3 √6 cm
See lessHimpunan Penyelesaian dari bentuk ke 5 2|2x-8|²-7|2x-8|-15=0
nilai mutlak 2|2x - 8|² - 7|2x - 8| - 15 = 0 2a² - 7a - 15 = 0 (2a + 3)(a - 5) = 0 a = -3/2 atau a = 5 a = -3/2 |2x - 8| = -3/2 TM tidak ada nilai x yg memenuhi a = 5 |2x - 8| = 5 2x - 8 = 5 atau 2x - 8 = -5 2x - 8 = 5 x = (5 + 8)/2 x = 13/2 2x - 8 = -5 x = (-5 + 8Read more
nilai mutlak
2|2x – 8|² – 7|2x – 8| – 15 = 0
2a² – 7a – 15 = 0
(2a + 3)(a – 5) = 0
a = -3/2 atau a = 5
a = –3/2
|2x – 8| = -3/2 TM
tidak ada nilai x yg memenuhi
a = 5
|2x – 8| = 5
2x – 8 = 5 atau 2x – 8 = -5
2x – 8 = 5
x = (5 + 8)/2
x = 13/2
2x – 8 = -5
x = (-5 + 8)/2
x = 3/2
HP = {3/2 , 13/2}
See lessSebuah tabung memiliki volume 36.960 cm³, jika tinggi tabung 15 cm, maka jari-jari tabung tersebut adalah
v = 36960 cm³ t = 15 cm v = πr² t r² = v/(πt) r² = 36960 / (22/7 × 15) r² = 36960 × 7/(22 × 15) r² = 784 r² = 28² r = 28 cm
v = 36960 cm³
t = 15 cm
v = πr² t
r² = v/(πt)
r² = 36960 / (22/7 × 15)
r² = 36960 × 7/(22 × 15)
r² = 784
r² = 28²
r = 28 cm
See less