Fungsi f ( x ) = x 3 + 3 x 2 − 9 x − 7 turun pada interval…
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Syarat suatu fungsi akan turun adalah turunan pertama kurang dari nol,
turunan pertama f(x)f(x) adalah f′(x)=3x2+6x−9f′(x)=3×2+6x−9
f′(x)<03x2+6x−9<0x2+2x−3<0(x+3)(x−1)<0<0diperoleh pembuat nolx=−3 ataux=1f′(x)<03×2+6x−9<0x2+2x−3<0(x+3)(x−1)<0<0diperoleh pembuat nolx=−3 ataux=1
Kesimpulan fungsi f(x)=x3+3x2−9x−7f(x)=x3+3×2−9x−7 turun pada interval −3<x<1−3<x<1