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sederhanakan dan nyatakan dalam pangkat positif
eksponen (x^-1 + y^-2) / (x^-2 - y^-1) → soal pd foto pembilang dan penyebut kalikan (x²y²) = (xy² + x²) / (y² - x²y) = x(y² + x) / y(y - x²)
eksponen
(x^-1 + y^-2) / (x^-2 – y^-1) → soal pd foto
pembilang dan penyebut kalikan (x²y²)
= (xy² + x²) / (y² – x²y)
= x(y² + x) / y(y – x²)
See lessNilai x dari 3x+³=3pangkat 6-x 2 LIHAT JAWABAN
Eksponen 3^(x + 3) = 3^(6 - x) x + 3 = 6 - x x + x = 6 - 3 2x = 3 x = 3/2 ^ baca pangkat
Eksponen
3^(x + 3) = 3^(6 – x)
x + 3 = 6 – x
x + x = 6 – 3
2x = 3
x = 3/2
^ baca pangkat
See lessTolong kakkkk..cuma 1 doangg kok
nilai mutlak |3x - 4| - 5 = 0 3x - 4 = 5 x = (5 + 4)/3 x = 3 atau 3x - 4 = -5 x = (-5 + 4)/3 x = -1/3 nilai x : x = 3 atau x = -1/3
nilai mutlak
|3x – 4| – 5 = 0
3x – 4 = 5
x = (5 + 4)/3
x = 3
atau
3x – 4 = -5
x = (-5 + 4)/3
x = -1/3
nilai x :
x = 3 atau x = -1/3
See lessTERIMAKASIH BUAT YANG JAWAB
Persamaan Trigonometri cos 3x = sin x cos 3x = cos (90 - x)° 3x = 90° - x + k.360° 3x + x = 90° + k.360° 4x = π/2 + k.2π x = π/8 + k.π/2 ... (1) cos 3x = sin x cos 3x = cos (270 + x)° 3x = 270° + x + k.360° 3x - x = 270° + k.360° 2x = 3π/2 + k.2π x = 3π/4 + k.π ... (2) k bilangaRead more
Persamaan Trigonometri
cos 3x = sin x
cos 3x = cos (90 – x)°
3x = 90° – x + k.360°
3x + x = 90° + k.360°
4x = π/2 + k.2π
x = π/8 + k.π/2 … (1)
cos 3x = sin x
cos 3x = cos (270 + x)°
3x = 270° + x + k.360°
3x – x = 270° + k.360°
2x = 3π/2 + k.2π
x = 3π/4 + k.π … (2)
k bilangan bulat
Interval [0 , 2π]
Substitusikan k ke persamaan (1) dan (2)
k = 0
x = π/8 atau x = 3π/4
k = 1
x = 5π/8 atau x = 7π/4
k = 2
x = 9π/8 atau x = 11π/4
k = 3
x = 13π/8
HP = {π/8, 5π/8, 3π/4, 9π/8, 13π/8, 7π/4}
See lessKubus ABCD.EFGH dengan rusuk 8 cm. Titik M berada ditengah tengah CD. Titik N terletak ditengah-tengah FG. Berapakah jarak antara titik M ke N ?
Dimensi Tiga Kubus r = 8 cm M tengah CD N tengah FG Jarak M ke N = MN = √(MC² + CG² + GN²) = √(4² + 8² + 4²) = √(16 + 64 + 16) = √(16 × 6) = 4√6 cm
Dimensi Tiga
Kubus
r = 8 cm
M tengah CD
N tengah FG
Jarak M ke N
= MN
= √(MC² + CG² + GN²)
= √(4² + 8² + 4²)
= √(16 + 64 + 16)
= √(16 × 6)
= 4√6 cm
See lessDalam suatu ujian dengan jumlah soal 50, jawabab yang benar diberi 2 nilai, salah -1, dan tidak menjawab 0. Dalam ujian seorang anak menjawab soal dengan benar sebanyak 39 soal, 8 soal tidak di jawab. Berapa nilai yang diperoleh siswa tersebut?
aljabar 50 soal 39 benar = 39 × 2 = 78 8 tidak dijawab = 0 3 salah = 3 × (-1) = -3 Nilai siswa = 78 + 0 + (-3) = 75
aljabar
50 soal
39 benar = 39 × 2 = 78
8 tidak dijawab = 0
3 salah = 3 × (-1) = -3
Nilai siswa = 78 + 0 + (-3) = 75
See lessMohon bantuannya kak, serta penjelasan ya ^_^
aljabar √a × √a = a • 6/√2 = (6/√2) × (√2 / √2) = 6√2 /2 = 3√2
aljabar
√a × √a = a
•
6/√2
= (6/√2) × (√2 / √2)
= 6√2 /2
= 3√2
See less