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Mohon bantuannya beserta diisi cara terima kasih
Dimensi Tiga Kubus r = 8 cm Rumus cepat Jarak F ke ACH = 2/3 DF = 2/3 r√3 = 2/3 × 8√3 = 16/3 √3 cm •• dengan cara O tengah BD P tengah FH R tengah AD HO = √(HD² + DR² + RO²) HO = 1/2 r√6 = 4√6 cm ∆FOH X pada HO FX ⊥ HO HF = r√2 cm Jarak F ke ACH = jarRead more
Dimensi Tiga
Kubus
r = 8 cm
Rumus cepat
Jarak F ke ACH
= 2/3 DF
= 2/3 r√3
= 2/3 × 8√3
= 16/3 √3 cm
••
dengan cara
O tengah BD
P tengah FH
R tengah AD
HO = √(HD² + DR² + RO²)
HO = 1/2 r√6 = 4√6 cm
∆FOH
X pada HO
FX ⊥ HO
HF = r√2 cm
Jarak F ke ACH
= jarak F ke HO
= HF × OP / HO
= r√2 × r / (1/2 r√6)
= 2r / √3
= 2/3 r√3
= 16/3 √3 cm
See lessdiketahui suku ke 6 barisan geometri adalah 1/8 dan rasionya 1/2 suku pertama dan barisan geometri tersebut
barisan geometri Un = ar^(n - 1) r = 1/2 U6 = 1/8 ar^(6 - 1) = 1/2³ ar⁵ = 2^-3 a(1/2)⁵ = 2^-3 a = 2^5 × 2^-3 a = 2^(5 + (-3)) a = 2² a = suku pertama = 4 4, 2, 1, 1/2 , ...
barisan geometri
Un = ar^(n – 1)
r = 1/2
U6 = 1/8
ar^(6 – 1) = 1/2³
ar⁵ = 2^-3
a(1/2)⁵ = 2^-3
a = 2^5 × 2^-3
a = 2^(5 + (-3))
a = 2²
a = suku pertama = 4
4, 2, 1, 1/2 , ...
See lessGalih akan memiliki persegi panjang dengan ukuran panjang 90 cm, dan lebar 72 cm, Galih ingin menutup permukaan persegi panjang tersebut dengan persegi-persegi yang berukuran sama. panjang sisi persegi terbesar yang dapat dibuat Galih adalah
bangun datar persegi panjang p = 90 cm l = 72 cm akan ditutup dg persegi kecil berukuran sama. panjang sisi terbesar yg dpt dibuat adalah FPB dari 90 dan 72. 90 = 2 × 3² × 5 72 = 2³ × 3² FPB dr 90 dan 72 = 2 × 3² = 18 sisi terbesar persegi yg dpt dibuat = 18 cmRead more
bangun datar
persegi panjang
p = 90 cm
l = 72 cm
akan ditutup dg persegi kecil berukuran sama.
panjang sisi terbesar yg dpt dibuat adalah FPB dari 90 dan 72.
90 = 2 × 3² × 5
72 = 2³ × 3²
FPB dr 90 dan 72 = 2 × 3² = 18
sisi terbesar persegi yg dpt dibuat = 18 cm
••
ABCD persegi panjang
AB = 90 cm
BC = 72 cm
persegi ungu → panjang sisi = 18 cm
See lessTentukan turunan dari y= x³ + 3 x/ sin x
turunan y = u/v → y' = (u'v - uv')/v² y = (x³ + 3x)/sin x u = x³ + 3x → u' = 3x² + 3 v = sin x → v' = cos x y' = ((3x² + 3)sin x - (x³ + 3x)cos x) / sin² x = (3x² + 3)sinx/sin² x - (x³ + 3x) cos x/sin² x = (3x² + 3)/sin x - (x³ + 3x) cotan x /sin x = (3x² + 3) cosec x - (x³ + 3xRead more
turunan
y = u/v → y’ = (u’v – uv’)/v²
y = (x³ + 3x)/sin x
u = x³ + 3x → u’ = 3x² + 3
v = sin x → v’ = cos x
y’
= ((3x² + 3)sin x – (x³ + 3x)cos x) / sin² x
= (3x² + 3)sinx/sin² x – (x³ + 3x) cos x/sin² x
= (3x² + 3)/sin x – (x³ + 3x) cotan x /sin x
= (3x² + 3) cosec x – (x³ + 3x) cotan x cosec x
See lessAkar 28 + 2 akar 63 – akar 700
aljabar √28 + 2√63 - √700 = √(4 × 7) + 2√(9 × 7) - √(100 × 7) = 2√7 + 2 . 3√7 - 10√7 = (√7)(2 + 6 - 10) = (√7) × (-2) = -2√7
aljabar
√28 + 2√63 – √700
= √(4 × 7) + 2√(9 × 7) – √(100 × 7)
= 2√7 + 2 . 3√7 – 10√7
= (√7)(2 + 6 – 10)
= (√7) × (-2)
= -2√7
See less7 akar 27 per 6 akar 3 =
aljabar 8√27 / 6√3 = 8/6 × √(27/3) = 8/6 × √9 = 8/6 × 3 = 8/2 = 4
aljabar
8√27 / 6√3
= 8/6 × √(27/3)
= 8/6 × √9
= 8/6 × 3
= 8/2
= 4
See lessBantu dong ini berapa hasilnya
eksponen a^m / a^n = a^(m - n) (a^m)^n = a^(mn) • (6/7)⁴ : (6/7)² = (6/7)^(4 - 2) = (6/7)² = 6²/7² = 36/49 • ((1/2)²)³ = (1/2)^(2 × 3) = (1/2)⁶ = 1⁶/2⁶ = 1/64
eksponen
a^m / a^n = a^(m – n)
(a^m)^n = a^(mn)
•
(6/7)⁴ : (6/7)²
= (6/7)^(4 – 2)
= (6/7)²
= 6²/7²
= 36/49
•
((1/2)²)³
= (1/2)^(2 × 3)
= (1/2)⁶
= 1⁶/2⁶
= 1/64
See less