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Bantuin kak jangan asal ya
eksponen (2x^-3 y²)³ = 2³ . (x^-3)³ . (y²)³ = 8 x^-9 . y⁶ = 8y⁶/x⁹
eksponen
(2x^-3 y²)³
= 2³ . (x^-3)³ . (y²)³
= 8 x^-9 . y⁶
= 8y⁶/x⁹
See lessKak bantuin 1 soal aja
eksponen (a/b)^-1 = b/a (-2/3k)³ × (-2/3k)^-4 = (-2/3k)^(3 + (-4)) = (-2/3k)^-1 = -3k/2
eksponen
(a/b)^-1 = b/a
(-2/3k)³ × (-2/3k)^-4
= (-2/3k)^(3 + (-4))
= (-2/3k)^-1
= -3k/2
See lessQuizzzz Match
dimensi tiga soal satu kubus r = 6 cm O tengah BE P tengah BF ∆BEG sama sisi Jarak G ke BE = jarak G ke tengah BE = GO = √(GF² + FP² + PO²) = √(6² + 3² + 3²) = √54 = 3√6 cm soal dua kubus r = 3 cm ∆AEG X pada AG EX ⊥ AG Jarak E ke AG = EX = AE × EG / AG = rRead more
dimensi tiga
soal satu
kubus
r = 6 cm
O tengah BE
P tengah BF
∆BEG sama sisi
Jarak G ke BE
= jarak G ke tengah BE
= GO
= √(GF² + FP² + PO²)
= √(6² + 3² + 3²)
= √54
= 3√6 cm
soal dua
kubus
r = 3 cm
∆AEG
X pada AG
EX ⊥ AG
Jarak E ke AG
= EX
= AE × EG / AG
= r × r√2 / r√3
= 1/3 r√6
= 1/3 × 3√6
= √6 cm
See lessTentukan nilai x yang memenuhi persamaan berikut: |x+1|²-5|x+1|=-6.
nilai mutlak |x + 1|² - 5|x + 1| = -6 a² - 5a + 6 = 0 (a - 2)(a - 3) = 0 a - 2 = 0 → a = 2 atau a - 3 = 0 → a = 3 a = 2 |x + 1| = 2 x + 1 = 2 x = 1 atau x + 1 = -2 x = -3 a = 3 |x + 1| = 3 x + 1 = 3 x = 2 x + 1 = -3 x = -4 Nilai x yang memenuhi : -4 , -3 , 1Read more
nilai mutlak
|x + 1|² – 5|x + 1| = -6
a² – 5a + 6 = 0
(a – 2)(a – 3) = 0
a – 2 = 0 → a = 2
atau
a – 3 = 0 → a = 3
a = 2
|x + 1| = 2
x + 1 = 2
x = 1
atau
x + 1 = -2
x = -3
a = 3
|x + 1| = 3
x + 1 = 3
x = 2
x + 1 = -3
x = -4
Nilai x yang memenuhi :
-4 , -3 , 1 , 2
See lessTentukan sistem pertidaksamaan linear yang sesuai dengan grafik dengan memilih Jawaban yang benar!Tolong bantu ya kak… Makasih ❤️
pertidaksamaan perhatikan titik potong pd sumbu x dan y • melalui (0,1) dan (4,0) 1x + 4y = 1 × 4 x + 4y = 4 arsiran menjauhi titik (0,0) tidak memuat (0,0) x + 4y ≥ 4
pertidaksamaan
perhatikan titik potong pd sumbu x dan y
• melalui (0,1) dan (4,0)
1x + 4y = 1 × 4
x + 4y = 4
arsiran menjauhi titik (0,0)
tidak memuat (0,0)
x + 4y ≥ 4
See lessTentukan sistem pertidaksamaan linear yang sesuai dengan grafik dengan memilih Jawaban yang benar!Tolong bantu dengan cara penyelesaiannya ya kak… Makasih (◍•ᴗ•◍)
persamaan garis melalui titik (0,a) dan (b,0) : ax + by = ab • melalui (0,2) dan (-3,0) 2x + (-3)y = 2 × (-3) 2x - 3y = -6 jawaban B
persamaan garis
melalui titik (0,a) dan (b,0) :
ax + by = ab
•
melalui (0,2) dan (-3,0)
2x + (-3)y = 2 × (-3)
2x – 3y = –6
jawaban B
See lessDengan menggunakan rumus trigonometri jumlah atau selisih 2 sudut,tentukanlah nilai dari 1.sin 165° 2.tan 15°
trigonometri sin (180° - a) = sin a sin (a - b) = sin a cos b - cos a sin b tan (a - b) = (tan a - tan b)/(1 + tan a tan b) • sin 165° = sin (180° - 15°) = sin 15° = sin (45° - 30°) = sin 45° cos 30° - cos 45° sin 30° = 1/2 √2 . 1/2 √3 - 1/2 √2 . 1/2 = 1/4 (√6 - √2) • tan 15° = tan (45Read more
trigonometri
sin (180° – a) = sin a
sin (a – b) = sin a cos b – cos a sin b
tan (a – b) = (tan a – tan b)/(1 + tan a tan b)
•
sin 165°
= sin (180° – 15°)
= sin 15°
= sin (45° – 30°)
= sin 45° cos 30° – cos 45° sin 30°
= 1/2 √2 . 1/2 √3 – 1/2 √2 . 1/2
= 1/4 (√6 – √2)
•
tan 15°
= tan (45° – 30°)
= (tan 45° – tan 30°) / (1 + tan 45° tan 30°)
= (1 – 1/√3) / (1 + 1.1/√3)
pembilang dan penyebut kalikan √3
= (√3 – 1) / (√3 + 1)
pembilang dan penyebut kalikan (√3 – 1)
= (√3 – 1)² / (3 – 1)
= (3 + 1 – 2√3)/2
= (4 – 2√3)/2
= 2 – √3
See less