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\lim_{(x + 5) \to 0} \: ( \frac{1 – \cos(x + 5) }{ {x}^{2} + 10x + 25 } )
limit 0/0 lim x→0 sin ax/bx = a/b • lim (x+5)→0 (1 - cos (x + 5)) / (x² + 10x + 25) = lim (x+5)→0 (1 - cos (x + 5)) / (x + 5)² = lim a→0 (1 - cos a)/a² = lim a→0 (2 sin² (a/2))/a² = 2 ((1/2) / 1)² = 2 × 1/4 = 1/2
limit 0/0
lim x→0 sin ax/bx = a/b
•
lim (x+5)→0 (1 – cos (x + 5)) / (x² + 10x + 25)
= lim (x+5)→0 (1 – cos (x + 5)) / (x + 5)²
= lim a→0 (1 – cos a)/a²
= lim a→0 (2 sin² (a/2))/a²
= 2 ((1/2) / 1)²
= 2 × 1/4
= 1/2
See less\lim_{x \to 0} \: ( \frac{ \tan(x) – \sin(x) }{x \cos(x) } )
limit 0/0 lim x→0 tan x /x = lim x→0 sin x /x = 1 • lim x→0 (tan x - sin x)/ (x cos x) = lim x→0 ((tan x /x) - (sin x /x))/cos x = (1 - 1) / 1 = 0
limit 0/0
lim x→0 tan x /x = lim x→0 sin x /x = 1
•
lim x→0 (tan x – sin x)/ (x cos x)
= lim x→0 ((tan x /x) – (sin x /x))/cos x
= (1 – 1) / 1
= 0
See lessTolong bantu jawab pakai cara
See lesstentukan himpunan penyelesaian |x+2|=3|×-4| tolong dibantu yaa
no 2 |x + 2| = 3|x - 4| |x + 2| = |3x - 12| (x + 2 + 3x - 12)(x + 2 - (3x - 12)) = 0 (4x - 10)(-2x + 14) = 0 x = 10/4 = 5/2 atau x = -14/-2 = 7 HP = {5/2 , 7}
no 2
|x + 2| = 3|x – 4|
|x + 2| = |3x – 12|
(x + 2 + 3x – 12)(x + 2 – (3x – 12)) = 0
(4x – 10)(-2x + 14) = 0
x = 10/4 = 5/2 atau x = -14/-2 = 7
HP = {5/2 , 7}
See lesstentukan nilai x yang memenuhi persamaan |4x -10|=-10
|4x - 10| = -10 nilai mutlak selalu bernilai positif, tidak mungkin bernilai (-10) negatif. tidak ada nilai x yg memenuhi HP = { }
|4x – 10| = -10
nilai mutlak selalu bernilai positif, tidak mungkin bernilai (-10) negatif.
tidak ada nilai x yg memenuhi
HP = { }
See lessJika diketahui x=√5 dan y=√7 , nilai √350 adalah
aljabar x = √5 → x² = 5 y = √7 √350 = √(2 × 5² × 7) = 5 × √2 × √7 = x² × √2 × y = √2 x²y = x²y√2
aljabar
x = √5 → x² = 5
y = √7
√350
= √(2 × 5² × 7)
= 5 × √2 × √7
= x² × √2 × y
= √2 x²y
= x²y√2
See lessMtk nihhhhhh……..
notasi ilmiah a × 10ⁿ 1 < a < 10 n bilangan bulat 0,000062 = 62/1000000 = 62 × 10^-6 = 6,2 × 10 × 10^-6 = 6,2 × 10^-5 • 125000000 = 125 × 1000000 = 1,25 × 100 × 1000000 = 1,25 × 10² × 10⁶ = 1,25 × 10⁸
notasi ilmiah
a × 10ⁿ
1 < a < 10
n bilangan bulat
0,000062
= 62/1000000
= 62 × 10^-6
= 6,2 × 10 × 10^-6
= 6,2 × 10^–5
•
125000000
= 125 × 1000000
= 1,25 × 100 × 1000000
= 1,25 × 10² × 10⁶
= 1,25 × 10⁸
See less