Akar 28 + 2 akar 63 – akar 700
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aljabar
√28 + 2√63 – √700
= √(4 × 7) + 2√(9 × 7) – √(100 × 7)
= 2√7 + 2 . 3√7 – 10√7
= (√7)(2 + 6 – 10)
= (√7) × (-2)
= -2√7